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%TCIDATA{Created=Tue Jun 08 12:47:04 2004}
%TCIDATA{LastRevised=Wednesday, June 11, 2008 10:40:54}
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\newtheorem{theorem}{Theorem}
\newtheorem{acknowledgement}[theorem]{Acknowledgement}
\newtheorem{algorithm}[theorem]{Algorithm}
\newtheorem{axiom}[theorem]{Axiom}
\newtheorem{case}[theorem]{Case}
\newtheorem{claim}[theorem]{Claim}
\newtheorem{conclusion}[theorem]{Conclusion}
\newtheorem{condition}[theorem]{Condition}
\newtheorem{conjecture}[theorem]{Conjecture}
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{criterion}[theorem]{Criterion}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{example}[theorem]{Example}
\newtheorem{exercise}[theorem]{Exercise}
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{notation}[theorem]{Notation}
\newtheorem{problem}[theorem]{Problem}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{solution}[theorem]{Solution}
\newtheorem{summary}[theorem]{Summary}
\newenvironment{proof}[1][Proof]{\textbf{#1.} }{\ \rule{0.5em}{0.5em}}
\begin{document}
El dominio de la funci\'{o}n $\sqrt{\dfrac{\left\vert x-1\right\vert
}{\left\vert 3x-6\right\vert }-2}$ es\medskip\newline\qquad a) $\left\{
2<x\leq\dfrac{11}{5}\right\}  ,\left\{  \dfrac{13}{7}\leq x<2\right\}  \qquad
$b) $\left\{  \dfrac{13}{7}\leq x\leq\dfrac{11}{5}\right\}  \medskip$%
\newline\qquad c) $\left\{  2<x<\dfrac{11}{5}\right\}  ,\left\{  \dfrac{13}%
{7}\leq x<2\right\}  \qquad$d) $\left\{  2<x<\dfrac{11}{5}\right\}  ,\left\{
\dfrac{13}{7}<x<2\right\}  $

El dominio de la funci\'{o}n $\sqrt{\dfrac{5}{\left\vert x-6\right\vert }-1}$
es\medskip\newline\qquad a) $\left\{  6<x\leq11\right\}  ,\left\{  1\leq
x<6\right\}  \qquad$b) $\left\{  1\leq x\leq6\right\}  \medskip$\newline\qquad
c) $\left\{  6<x<11\right\}  ,\left\{  1\leq x<6\right\}  \qquad$d) $\left\{
6<x<11\right\}  ,\left\{  1<x<6\right\}  $

El dominio de la funci\'{o}n $\sqrt{5x^{2}-1}$ es\newline\qquad a) $\left\{
x\leq-\dfrac{\sqrt{5}}{5}\right\}  ,\left\{  \dfrac{\sqrt{5}}{5}\leq
x\right\}  \qquad$b) $\left\{  -\sqrt{5}\leq x\leq\sqrt{5}\right\}  \medskip
$\newline\qquad c) $\left\{  -\dfrac{\sqrt{5}}{5}\leq x\leq\dfrac{\sqrt{5}}%
{5}\right\}  \qquad$d) $\left\{  x<-\dfrac{\sqrt{5}}{5}\right\}  ,\left\{
\dfrac{\sqrt{5}}{5}<x\right\}  $

El dominio de la funci\'{o}n $\sqrt{\dfrac{4}{\left\vert 2x-3\right\vert }+1}$
es\medskip\newline a) $\left\{  x:x\neq\dfrac{3}{2}\right\}  \qquad$b)
$\left\{  -\dfrac{3}{2}\leq x\leq\dfrac{3}{2}\right\}  \medskip$\newline c)
$\left\{  -\dfrac{3}{2}<x<\dfrac{3}{2}\right\}  \qquad$d) $\left\{
x<-\dfrac{3}{2}\right\}  ,\left\{  \dfrac{3}{2}<x\right\}  $

El dominio de la funci\'{o}n $\sqrt{\dfrac{1}{\left\vert x-3\right\vert }-5}$
es\medskip\newline\qquad a) $\left\{  \dfrac{14}{5}\leq x<3\right\}  ,\left\{
3<x\leq\dfrac{16}{5}\right\}  \qquad$b) $\left\{  3<x\leq\dfrac{16}%
{5}\right\}  \medskip$\newline\qquad c) $\left\{  \dfrac{14}{5}<x<3\right\}
,\left\{  3<x<\dfrac{16}{5}\right\}  \qquad$d) $\left\{  \dfrac{14}{5}\leq
x<3\right\}  $

El dominio de la funci\'{o}n $\sqrt{\dfrac{3}{\left\vert x-4\right\vert }+1}$
es\medskip\ \newline\qquad a) $\left\{  4<x\right\}  ,\left\{  4<x\right\}
$\qquad b) $\left\{  x<4\right\}  \medskip$\newline\qquad c) $\left\{  4\leq
x\right\}  ,\left\{  x<9\right\}  $\qquad d) $\left\{  4<x<10\right\}
,\left\{  -10<x<4\right\}  $

El dominio de la funci\'{o}n $\sqrt{\dfrac{1}{\left\vert x-7\right\vert }-1}$
es \newline\qquad a) $\left\{  6\leq x<7\right\}  \{7<x\leq8\}$\qquad b)
$\left\{  6<x<7\right\}  ,\left\{  7<x<11\right\}  \medskip$\newline\qquad c)
$\left\{  6<x\leq11\right\}  ,\left\{  1\leq x<6\right\}  $\qquad d) $\left\{
6<x<7\right\}  ,\left\{  7\leq x<8\right\}  $

El dominio de la funci\'{o}n $\sqrt{\dfrac{5}{\left\vert x-5\right\vert }-2}$
es \medskip\newline\qquad a) $\left\{  \dfrac{5}{2}\leq x<5\right\}  \left\{
5<x\leq\dfrac{15}{2}\newline\right\}  $\qquad b) $\left\{  \dfrac{5}%
{2}<x<5\right\}  ,\left\{  5\leq x<\dfrac{15}{2}\right\}  \medskip$%
\newline\qquad c) $\left\{  \dfrac{5}{2}<x\leq5\right\}  ,\left\{  5\leq
x<\dfrac{15}{2}\right\}  $\qquad d) $\left\{  5<x<\dfrac{15}{2}\right\}
,\left\{  \dfrac{5}{2}\leq x<5\right\}  $

El dominio de la funci\'{o}n $\sqrt{\dfrac{7}{\left\vert x-1\right\vert }-3}$
es \medskip\newline\qquad a) $\left\{  -\dfrac{4}{3}\leq x<1\right\}
,\left\{  1<x\leq\dfrac{10}{3}\right\}  $\qquad b) $\left\{  -\dfrac{4}{3}\leq
x\leq\dfrac{10}{3}\right\}  \medskip$\newline\qquad c) $\left\{  -\dfrac{4}%
{3}<x\leq1\right\}  ,\left\{  1<x\leq\dfrac{10}{3}\right\}  $\qquad d)
$\left\{  -\dfrac{4}{3}<x<1\right\}  ,\left\{  1<x<\dfrac{10}{3}\right\}  $

El dominio de la funci\'{o}n $\sqrt{\dfrac{6}{\left\vert x-8\right\vert }-7}$
es \medskip\newline\qquad a) $\left\{  \dfrac{50}{7}\leq x<8\right\}
,\left\{  8<x\leq\dfrac{62}{7}\right\}  \qquad$b) $\left\{  \dfrac{50}%
{7}<x<8\right\}  ,\left\{  8<x\leq\dfrac{62}{7}\right\}  \medskip$%
\newline\qquad c) $\left\{  \dfrac{50}{7}<x<8\right\}  ,\left\{
8<x<\dfrac{62}{7}\right\}  \qquad$d) $\left\{  \dfrac{50}{7}\leq x\leq
\dfrac{62}{7}\right\}  $

El dominio de la funci\'{o}n $\sqrt{\dfrac{12}{\left\vert x-3\right\vert }-2}$
es \medskip\newline\qquad a) $\left\{  -3\leq x<3\right\}  ,\left\{
3<x\leq9\right\}  $\qquad b) $\left\{  3<x<9\right\}  ,\left\{  -3\leq
x<3\right\}  $ \medskip\newline\qquad c) $\left\{  -3\leq x\leq9\right\}
$\qquad\qquad\qquad\qquad d) $\left\{  -3<x\leq3\right\}  ,\left\{  3\leq
x<9\right\}  $

El dominio de la funci\'{o}n $\sqrt{\dfrac{5}{\left\vert x-9\right\vert }+2}$
es \medskip\newline\qquad a) $\left\{  9<x\right\}  ,\left\{  9<x\right\}
$\qquad\qquad\qquad\qquad b) $\left\{  x<9\right\}  \medskip$\newline\qquad c)
$\left\{  9<x<10\right\}  ,\left\{  -10<x<9\right\}  \qquad$d) $\left\{  9\leq
x\right\}  ,\left\{  x<14\right\}  $

El dominio de la funci\'{o}n $\sqrt{3-\dfrac{2}{\left\vert x-4\right\vert }}$
es\medskip\ \newline\qquad a) $\left\{  x\leq\dfrac{10}{3}\right\}  ,\left\{
\dfrac{14}{3}\leq x\right\}  \qquad$\qquad b) $\left\{  \dfrac{10}{3}\leq
x\leq\dfrac{14}{3}\right\}  \medskip$\newline\qquad c) $\left\{  \dfrac{10}%
{3}<x<4\right\}  ,\left\{  4\leq x<\dfrac{14}{3}\right\}  $\qquad d) $\left\{
4<x<\dfrac{14}{3}\right\}  ,\left\{  \dfrac{10}{3}<x<4\right\}  $

El dominio de la funci\'{o}n $\sqrt{5-\dfrac{3}{\left\vert x-4\right\vert }}$
es \medskip\newline\qquad a) $\left\{  x\leq\dfrac{17}{5}\right\}  ,\left\{
\dfrac{23}{5}\leq x\right\}  \qquad\qquad$\qquad b) $\left\{  \dfrac{17}%
{5}\leq x\leq\dfrac{23}{5}\right\}  \medskip$\newline\qquad c) $\left\{
\dfrac{17}{5}<x\leq4\right\}  ,\left\{  4\leq x<\dfrac{23}{5}\right\}  $\qquad
d) $\left\{  4<x<\dfrac{23}{5}\right\}  ,\left\{  \dfrac{17}{5}<x<4\right\}  $

El dominio de la funci\'{o}n $\sqrt{7-\dfrac{5}{\left\vert x-8\right\vert }}$
es \medskip\newline\qquad a) $\left\{  x\leq\dfrac{51}{7}\right\}  ,\left\{
\dfrac{61}{7}\leq x\right\}  $\qquad\qquad\qquad b) $\left\{  \dfrac{51}%
{7}\leq x\leq\dfrac{61}{7}\right\}  \medskip$\newline\qquad c) $\left\{
8<x<\dfrac{61}{7}\right\}  ,\left\{  \dfrac{51}{7}\leq x<8\right\}  $\qquad d)
$\left\{  8<x<\dfrac{61}{7}\right\}  ,\left\{  \dfrac{51}{7}<x<8\right\}  $


\end{document}